How do you graph $y = \frac{1}{4} sec x$ $y=1/4secx$ and include two full periods?

Question

2478 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-24T03:23:04

As below

$y = (\frac{1}{4}) sec x$ $y = (1/4) sec x$

Standard form of secant function is $y = A sec (B x - C) + D$ $y = A sec(Bx - C) + D$

$A = \frac{1}{4}, B = 1, C = D = 0$ $A = 1/4, B = 1, C = D = 0$

$A m p l i t u d e = | A | = NONE for secant function$ $Amplitude = |A| = "NONE for secant function"$

$Period = \frac{2 π}{| B |} = 2 π$ $"Period " = (2pi) / |B| = 2pi$

$Phase Shift = - \frac{C}{B} = 0$ $"Phase Shift " = -C / B = 0$

$Vertical Shift = D = 0$ $"Vertical Shift " = D =0$

graph{(1/4) sec(x) [-10, 10, -5, 5]}

How do you graph y=14secxy=1/4secx and include two full periods?