How do you graph $y=1/2csc(2x)$ ?

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Answer 1 · 2018-06-24T03:02:01

As below.

$y = (1/2) csc (2x)$

Standard form of cosecant function is $y = A csc(Bx - C) + D$

$A = 1/2, B = 2, C = D = 0$

$Amplitude = |A| = "NONE for cosecant function"$

$"Period " = (2pi) / |B| = (2pi) / 2 = pi$

$"Phase Shift " = -C / B = 0$

$"Vertical Shift " = D = 0$

graph{(1/2) csc(2x) [-10, 10, -5, 5]}

How do you graph y=1/2csc(2x)y=1/2csc(2x)?