How do you graph #y= (1/2)x#? Algebra Graphs of Linear Equations and Functions Graphs Using Slope-Intercept Form 1 Answer ali ergin Apr 18, 2016 #"for "x=0" "y=0# #"for "y=0" "x=0# Explanation: #y=1/2x# #"for "x=0" "y=0# #"for "x=1" "y=1/2# #"for "x=2" "y=1# #"for "x=3" "y=3/2# #..................................# #..................................# #"for "y=0" "x=0# #"for "y=1" "x=2# #"for "y=2" "x=4# #"for "y=3" "x=6# Answer link Related questions How do you graph #2x-3y=6# using slope intercept form? How do you graph a line using slope-intercept form? Does a graph always have a y-intercept? Where is the y-intercept of #y=2x+0.5# on a graph? How do you graph #y=-3x+5# using slope intercept form? Once you graph the y-intercept, how do you determine the second point? How do you know if you graphed the linear equation correctly? How do you graph #y=-\frac{1}{5}x-11#? How do you graph #2x + 5y = 10# using the slope and y-intercept? How do you graph #3x-5y= 10# using the slope and y intercept? See all questions in Graphs Using Slope-Intercept Form Impact of this question 2349 views around the world You can reuse this answer Creative Commons License