How do you graph $y=1/2 tan(pi/4 x + pi/4)$ ?

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Answer 1 · 2018-06-26T01:40:32

As below.

Standard form of tangent function is $y = A tan (Bx - C) + D$

$"Given : " y = (1/2) tan ((pi/4)x + pi/4)$

$A = 1/2, b = pi/4, c = -pi/4, D = 0$

$"Amplitude " = |A| = "NONE for tangent function"$

$"Period " = pi/|B| = pi/ (pi/4) = 4$

$"Phase Shift" = -C / B = -(pi/4) / (pi/4) = -1, " 1 to the LEFT"$

$"Vertical Shift " = D = 0$

graph{(1/2) tan((pi/4)x + pi/4) [-10, 10, -5, 5]}

How do you graph y=1/2 tan(pi/4 x + pi/4)y=1/2 tan(pi/4 x + pi/4)?