How do you graph using x and y intercept of $3 x - 4 y + 2 = 0$ $3x-4y+2=0$ ?

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How do you graph using x and y intercept of $3 x - 4 y + 2 = 0$ $3x-4y+2=0$ ?

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Answer 1 · 2017-03-14T16:49:30

Please see below.

Explanation:

We can find $x$ $x$ -intercept by putting $y = 0$ $y=0$ in the given equation $3 x - 4 y + 2 = 0$ $3x-4y+2=0$ and $y$ $y$ -intercept by putting $y = 0$ $y=0$ in the equation.

Hence $x$ $x$ -intercept is given by $3 x - 4 \times 0 + 2 = 0$ $3x-4xx0+2=0$ i.e. $x = - \frac{2}{3}$ $x=-2/3$ at $(- \frac{2}{3}, 0)$ $(-2/3,0)$

and $y$ $y$ -intercept is given by $3 \times 0 - 4 y + 2 = 0$ $3xx0-4y+2=0$ i.e. $y = \frac{1}{2}$ $y=1/2$ at $(0, \frac{1}{2})$ $(0,1/2)$

The graph will be obtained by joining $(- \frac{2}{3}, 0)$ $(-2/3,0)$ and $(0, \frac{1}{2})$ $(0,1/2)$ and appears as given below.

graph{3x-4y+2=0 [-3.177, 1.823, -1.28, 1.22]}

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How do you graph using x and y intercept of $3 x - 4 y + 2 = 0$ $3x-4y+2=0$ ?

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