How do you graph using slope and intercept of #-x+5y=-5#?

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Answer 1 · 2015-11-10T23:01:05

The slope is #1/5#.
The y-intercept is #-1#.
The x-intercept is #5#.

#-x+5y=-5# is a linear equation in standard form. Convert it to the slope intercept form by solving for #y#.

#-x+5y=-5#

Add #x# to both sides.

#5y=x-5#

Divide both sides by #5#.

#y=x/5-5/5=#

#y=1/5x-1#

#y=1/5x-1# is the slope intercept form of a linear equation, #y=mx+b#, where #m# is the slope, #1/5# and #b# is the y-intercept, #-1#.

The y-intercept is the value of #y# when #x=0#. The point of the y-intercept is #(0,-1)#.

The x-intercept is the value of #x# when #y=0#.

#0=1/5x-1#

Add #1# to both sides.

#1=1/5x#

Multiply both sides times #5#.

#1*5=1/cancel5x*cancel5=#

#5=x#

Switch sides.

#x=5#

The x-intercept is #5#. The point of the x-intercept is #(5,0)#.

Plot the two points and draw a straight line through the points.

graph{y=1/5x-1 [-16.02, 16, -8.01, 8.01]}