How do you graph using slope and intercept of #8x - 6y = -20#?

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Answer 1 · 2018-07-04T02:38:38

See below:

When an equation is in slope-intercept form

#y=mx+b#, we know that #m# is the slope and #b# is the #y#-intercept.

In our example, we only want a #y# on the left side, so we can start by subtracting #8x# from both sides to get

#-6y=-8x-20#

Divide all terms by #-6# to get

#y=4/3x+10/3#

We can start at our #y#-intercept, and from that point, go up #4# in the #y#-direction and right #3# in the #x#-direction. We get the graph

graph{y=4/3x+10/3 [-10, 10, -5, 5]}

Hope this helps!