How do you graph using slope and intercept of 8x - 6y = -20?

1 Answer
Jul 4, 2018

See below:

Explanation:

When an equation is in slope-intercept form

y=mx+b, we know that m is the slope and b is the y-intercept.

In our example, we only want a y on the left side, so we can start by subtracting 8x from both sides to get

-6y=-8x-20

Divide all terms by -6 to get

y=4/3x+10/3

We can start at our y-intercept, and from that point, go up 4 in the y-direction and right 3 in the x-direction. We get the graph

graph{y=4/3x+10/3 [-10, 10, -5, 5]}

Hope this helps!