How do you graph using slope and intercept of #2x-y=5#?

So we want it in slope which is #y=mx+b# but this is in standard form.

So let start by rewriting the equation

#2x-y=5#

Now, we subtract #2x# from both sides which gives us:

#-y=-2x+5#

Now, the variable #y# can never be a negative numbers, so we divide everything by negative one which changes the sign to this:

#y=2x-5#

Now, you can plug in any numbers for x that gives you an input for y.

So let plug in 2 values for x.

#y=2(-1)-5#
#y=-2-5# - Distribute the 2 to the number inside the parentheses
#y=-7#

So now we know when we plug in #-1# for x, we got a output of #y=-7# but we need to put this as a coordinate point so we can graph this.

So to do this, it goes like this #(x, y)#. So whatever you plug in for x, you put it as the first number. Output is where you put it in the second place.

So let plug in 7 for x this time.

#y=2(7)-5#
#y=14-5#
#y=9#

So we need to put this as a coordinate point which would be #(7,9)#.

The y-intercept of this equation is #(0,-5)#

Your graph will look like this:
graph{y=2x-5 [-10, 10, -5, 5]}

Ensure that you use a straight edge or something that is straight to draw a straight line.