How do you graph to solve the equation on the interval #[-2pi,2pi]# for #tanx=1#?

1 Answer
tcw1
Aug 1, 2017

(#-(7pi)/4,-(3pi)/4,pi/4,(5pi)/4#)

Explanation:

Solving for x:
#tanx=1#
#x=arctan1#
When the tangent of an angle is 1, we know that the lengths of the non hypotenuse sides are equal and have the same sign. So: Please excuse the MS Paint
We know that the values of angles x and y are #pi/4#, and we need to add those values to known values on the interval. The solutions will be (#-2pi+pi/4#, #-pi+pi/4#, #pi/4#, #pi+pi/4#), which simplifies to:

(#-(7pi)/4,-(3pi)/4,pi/4,(5pi)/4#)

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