How do you graph to solve the equation on the interval [-2pi,2pi] for tanx=1?

1 Answer
tcw1
Aug 1, 2017

(-(7pi)/4,-(3pi)/4,pi/4,(5pi)/4)

Explanation:

Solving for x:
tanx=1
x=arctan1
When the tangent of an angle is 1, we know that the lengths of the non hypotenuse sides are equal and have the same sign. So: Please excuse the MS Paint
We know that the values of angles x and y are pi/4, and we need to add those values to known values on the interval. The solutions will be (-2pi+pi/4, -pi+pi/4, pi/4, pi+pi/4), which simplifies to:

(-(7pi)/4,-(3pi)/4,pi/4,(5pi)/4)

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