How do you graph to solve the equation on the interval $[- 2 π, 2 π]$ $[-2pi,2pi]$ for $csc x = \sqrt{2}$ $cscx=sqrt2$ ?

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How do you graph to solve the equation on the interval $[- 2 π, 2 π]$ $[-2pi,2pi]$ for $csc x = \sqrt{2}$ $cscx=sqrt2$ ?

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Answer 1 · 2017-11-13T20:57:31

See below.

Explanation:

enter image source here

Since you will be graphing $y = csc (x)$ $y=csc(x)$ this is the same as $y = \frac{1}{cos x}$ $y=1/cosx$

Notice from the graph that the vertical lines are asymptotes. This is because $y = \frac{1}{cos x}$ $y=1/cosx$ is undefined anywhere $cos x = 0$ $cosx=0$ .

( this results in division by zero ).

Graph the line $y = \sqrt{2}$ $y = sqrt(2)$ on the same plot. Where $y = \sqrt{2}$ $y=sqrt(2)$ cuts the curves, not the asymptotes, are the solutions to $csc x = \sqrt{2}$ $cscx=sqrt(2)$ . It's very difficult to get accurate solutions from a graph though.

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How do you graph to solve the equation on the interval $[- 2 π, 2 π]$ $[-2pi,2pi]$ for $csc x = \sqrt{2}$ $cscx=sqrt2$ ?

1 Answer

Explanation:

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How do you graph to solve the equation on the interval [−2π,2π][-2pi,2pi] for cscx=√2cscx=sqrt2?

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Explanation:

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How do you graph to solve the equation on the interval $[- 2 π, 2 π]$ $[-2pi,2pi]$ for $csc x = \sqrt{2}$ $cscx=sqrt2$ ?