How do you graph to solve the equation on the interval $[-2pi,2pi]$ for $cotx=-sqrt3/3$ ?

Question

8523 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-08-05T12:02:13

Solution : In interval $[-2pi,2pi] , x= -pi/3 = -60^0, x = -(4pi)/3=-240^0 x= (2pi)/3=120^0 , x = (5pi)/3=300^0$

$tan (pi/3) =3/sqrt3 :. cot (pi/3) =sqrt (3)/3 or cot (pi-pi/3) = -sqrt (3)/3$

$cot x = -sqrt (3)/3 :. x = (pi-pi/3) = (2pi)/3 ; x =pi+ (2pi)/3 = (5pi)/3$

$(5pi)/3 =((2pi)-(5pi)/3)= -pi/3 :. x = -pi/3;$

$(2pi)/3 =((2pi)-(2pi)/3)= -(4pi)/3 :. x = -(4pi)/3$

Solution : In interval $[-2pi,2pi] , x= -pi/3 = -60^0, x = -(4pi)/3=-240^0 x= (2pi)/3=120^0 , x = (5pi)/3=300^0$ [Ans]

How do you graph to solve the equation on the interval [-2pi,2pi][-2pi,2pi] for cotx=-sqrt3/3cotx=-sqrt3/3?