How do you graph the lines using slope-intercept form #h(x) = -x+7#?
1 Answer
Feb 1, 2016
graph{-x+7 [-10, 10, -5, 5]}
Explanation:
1) Use the equation and what we know about slope-intercept form to find the slope and y-intercept.
The slope-intercept form equation is:
Therefore, the slope (
2) Find the *x-intercept*
Set the equation equal to
So the x-intercept is (7,0)
3) Use what we know to create a graph
- Because of the y-intercept , we know the graph crosses the y-axis at
#(0,7)# . - Because of the x-intercept, we know that the graph crosses the x-axis at
#(7,0)# - Because the slope is negative, we know that the graph is going down.
- Because the slope is rise over run we can use up 1 over 1 to graph a few points and create a line
OR
Create a table or list of coordinates by:
#x-1# ,#y+1# if using the x-intercept. So:#(7,0), (6,1), (5,2),# etc.
or
#x+1, y-1# if using the y-intercept. So:#(0,7), (1,6), (2,5)# , etc.
