# How do you graph the line #f(x) = 3-2x #?

##### 1 Answer

Explanation below.

#### Explanation:

Start off by rearranging the equation to make it into y=mx+b form (m = slope, b = y-intercept).

So,

To find the starting point to this graph, we can use the y-intercept. In this case, the y-intercept is 3 (the line crosses the y-axis at 3), so the starting point would be at

We can now use the slope to find the rest of the points to graph this line.

The slope here will be

As we know, the slope is "rise over run"; "rise" meaning we would go up/down a certain number of units and "run" meaning going horizontally to the left/right.

In this case, we would go 2 units down because it is a negative slope, and 1 unit to the right. Keep doing this to find the rest of the points, plot them, and draw a straight line. Extending the line in both directions.

graph{-2x+3 [-8.89, 8.89, -4.444, 4.445]}

The graph shows the starting point;

Hope this helped!