# How do you graph the inequality 3x + y> 1?

May 31, 2016

#### Explanation:

For drawing the graph of a linear inequality, one needs to first draw the graph of the equation (i.e. with 'equal(=)' sign), which is a straight line.

Now this line divides the Cartesian Plane in three parts - (a) the line itself, on which every point satisfies the equality; (b) this line divides plane in two parts, and in one of them the function will satisfy 'greater than' condition and in the other, it will satisfy 'less than' condition.

Let us draw the graph of $3 x + y = 1$. In this, When $x = 0$, $y = 1$.

If $x = 3$, $y = - 8$ and when $x = - 5$, $y = 16$.

Now the line joining $\left(0 , 1\right)$, $\left(3 , - 8\right)$ and $\left(- 5 , 16\right)$ gives the graph of the line and $3 x + y > 1$ is the portion on right hand side of the line. The line is marked as dotted as the points on the line are not included in the solution.