How do you graph, identify the domain, range, and asymptotes for y=tan(2x+pi/2)y=tan(2x+π2)?

1 Answer
Jul 25, 2018

Domain: x ne k/2pi, k = 0, +- 1, +- 2, +- 3, ..xk2π,k=0,±1,±2,±3,..
Range: ( - oo, oo )(,).
Asymptotes: x = k/2pi, k = 0, +- 1, +- 2, +- 3, ..x=k2π,k=0,±1,±2,±3,... See grapj.

Explanation:

y = tan ( 2x + pi/2 ) = - cot 2x, y=tan(2x+π2)=cot2x,

x ne 0, +- pi/2, +- pi, +- 3/2 pi, +-2pi, ...

Graph of y = tan ( 2x + pi/2 ):
graph{y-tan(2x+pi/2)=0}