How do you graph $f(x) = sec (pi x)$ ?

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Answer 1 · 2018-07-10T16:19:42

As below

$f(x) = sec (pi x)$

Standard form of equation for secant function is $y = A sec(Bx - C) + D$

$A = 1, B = pi, C = D = 0$

$Amplitude = |A| = NONE$ for Secant function

Period $= (2pi) / |B| = (2pi)/pi = 2$

graph{sec (pi x) [-10, 10, -5, 5]}

How do you graph f(x) = sec (pi x) f(x) = sec (pi x)?