How do you graph #6x-4y=16#?

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Answer 1 · 2017-08-31T12:04:09

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point:

For #x = 0#

#(6 * 0) - 4y = 16#

#0 - 4y = 16#

#-4y = 16#

#(-4y)/color(red)(-4) = 16/color(red)(-4)#

#y = -4# or #(0, -4)#

Second Point:

For #x = 2#

#(6 * 2) - 4y = 16#

#12 - 4y = 16#

#-color(red)(12) + 12 - 4y = -color(red)(12) + 16#

#0 - 4y = 4#

#-4y = 4#

#(-4y)/color(red)(-4) = 4/color(red)(-4)#

#y = -1# or #(2, -1)#

We can next graph the two points on the coordinate plane:

graph{(x^2+(y+4)^2-0.08)((x-2)^2+(y+1)^2-0.08)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(6x-4y-16)(x^2+(y+4)^2-0.08)((x-2)^2+(y+1)^2-0.08)=0 [-20, 20, -10, 10]}