How do you graph $3x-y=7$ ?

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Answer 1 · 2017-07-22T04:11:35

Plot the points $(3.3,0) ; (0,-7)$
Join these two points you will get the curve.

Given -

$3x-y=7$

Find the two intercepts. Plot them and
join them with a straight line.

x-intercept
At $y=0$

$3x-0=7$
$x=7/3=3.3$
$(3.3,0)$

y-intercept
At $x=0$

$3(0)-y=7$
$y=-7$
$(0,-7)$

Plot the points $(3.3,0) ; (0,-7)$
Join these two points you will get the curve.

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Answer 2 · 2017-07-22T04:16:51

I would rearrange the equation into standard form: $y = 3x-7$

This means that the line has a gradient (slope) of $3$ , and a y-intercept of $-7$ .

Graph the function by drawing a line through the point $(0,-7)$ with a gradient of $3$ .

$3x-y=7$

Subtract $3x$ from both sides:

$-y=-3x+7$

Multiply both sides by $-1$ :

$y = 3x-7$

This means that the line has a gradient (slope) of $3$ , and a y-intercept of $-7$ .

How do you graph 3x-y=73x-y=7?