How do you graph $3 x - y = 7$ $3x-y=7$ ?

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Answer 1 · 2017-07-22T04:11:35

Plot the points $(3.3, 0); (0, - 7)$ $(3.3,0) ; (0,-7)$
Join these two points you will get the curve.

Given -

$3 x - y = 7$ $3x-y=7$

Find the two intercepts. Plot them and
join them with a straight line.

x-intercept
At $y = 0$ $y=0$

$3 x - 0 = 7$ $3x-0=7$
$x = \frac{7}{3} = 3.3$ $x=7/3=3.3$
$(3.3, 0)$ $(3.3,0)$

y-intercept
At $x = 0$ $x=0$

$3 (0) - y = 7$ $3(0)-y=7$
$y = - 7$ $y=-7$
$(0, - 7)$ $(0,-7)$

Plot the points $(3.3, 0); (0, - 7)$ $(3.3,0) ; (0,-7)$
Join these two points you will get the curve.

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Answer 2 · 2017-07-22T04:16:51

I would rearrange the equation into standard form: $y = 3 x - 7$ $y = 3x-7$

This means that the line has a gradient (slope) of $3$ $3$ , and a y-intercept of $- 7$ $-7$ .

Graph the function by drawing a line through the point $(0, - 7)$ $(0,-7)$ with a gradient of $3$ $3$ .

$3 x - y = 7$ $3x-y=7$

Subtract $3 x$ $3x$ from both sides:

$- y = - 3 x + 7$ $-y=-3x+7$

Multiply both sides by $- 1$ $-1$ :

$y = 3 x - 7$ $y = 3x-7$

This means that the line has a gradient (slope) of $3$ $3$ , and a y-intercept of $- 7$ $-7$ .

How do you graph 3x-y=73x−y=73x-y=7?