How do you graph #-2x+7y=-7# by plotting points?

1 Answer
Alan P.
Jun 17, 2018

Here is the graph with two key points indicated by small circles:
graph{(x^2+(y+1)^2-0.005)((x-(7/2))^2+y^2-0.005)(7-2x+7y)=0 [-0.376, 5.1, -1.764, 0.97]}

Explanation:

Since the given equation: #-2x+7y=-7# is linear,
we only need 2 points to establish the required line.

The simplest points to evaluate are
[1]#color(white)("XXX")#when #x=0rarr (x,y)=(0,-1)#
[2]#color(white)("XXX")#when #y=0rarr (x,y)=(7/2,0)#

If we plot these points on the Cartesian plane and draw a straight line through them we will get the required graph.

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