How do you graph $- 2 tan 3 (x - 30) + 1$ $-2tan3(x - 30) + 1$ ?

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How do you graph $- 2 tan 3 (x - 30) + 1$ $-2tan3(x - 30) + 1$ ?

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Answer 1 · 2018-07-29T11:55:01

See graph and details.

Explanation:

$y = - 2 tan (3 (x - \frac{π}{6})) + 1$ $y = - 2 tan (3 ( x - pi/ 6 ) ) +1$ , asymptotic

$3 ( x - pi/ 6 ) ne { ( 2 k + 1 ) pi/2 }, k = 0, +-1, +-2, +-3, ...$

$rArr x ne { ( 2 k + 2 ) pi/6 } = { 2k ( pi/ 6 ) } ={ k (pi/3) }$

The period = the period of $tan 3x = pi/3$ . See graph, with

asymptotes.
graph{(1/2(y-1)cos(3(x+pi/4))+sin(3(x+pi/4)))(x-1/3pi+0.0001y)(x+1/3pi+0.0001y)(x-2/3pi+0.0001y)(x+2/3pi+0.0001y)(x-pi+0.0001y)(x+pi+0.0001y)=0[ -4 4 -2 2]}

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How do you graph $- 2 tan 3 (x - 30) + 1$ $-2tan3(x - 30) + 1$ ?

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Explanation:

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How do you graph $- 2 tan 3 (x - 30) + 1$ $-2tan3(x - 30) + 1$ ?