How do you find two consecutive even integers such that twice the smaller is 26 less than 3 times the larger?

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Answer 1 · 2016-10-30T10:00:10

The numbers are # 20 and 22#

First use a variable to define the two unknown numbers.

Let the smaller even number be #x#
The larger number is #x+2#

"Twice the smaller": #2x#

"3 times the larger": #3(x+2)#

These two numbers differ by 26.

"Bigger value - smaller value " = #26#

#3(x+2) - 2x = 26" "larr# here is the equation. Solve it.

#3x+6 -2x = 26#

#x = 26-6#

#x = 20#

#20# is the smaller number, The larger is #22#

Check:

#3xx22 = 66" and "2 xx 2 = 40#

#66-40 =26#