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How do you find the zeros of #y=3x^2+2x#?

1 Answer

Mar 5, 2017

#x=0# or #x=-2/3#

Explanation:

#y= 3x^2+2x#

#= x(3x+2)#

The zeros of #y# are those values of #x# such that #y=0#

I.e. where #x(3x+2) =0#

#:. x=0# or #3x+2=0#

Hence: #x=0# or #x=-2/3#

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