How do you find the x and y intercepts for #f(x)=x^2-9x+14#?

1 Answer
Alan P.
Jan 20, 2016

y-intercept: #14#
x-intercepts: #2# and #7#

Explanation:

Note that #y# is equivalent to #f(x)#
So we can think of the given equation as
#color(white)("XXX")y=x^2-9x+14#

The y-intercept is the value of #y# when #x=0#.
Given the form of the equation above, clearly:
#color(white)("XXX")#y-intercept #=14#

The x-intercept(s) is/are the value(s) of #x# for which #y=0#
#color(white)("XXX")x^2-9x+14=0#

#rarrcolor(white)("X")(x-7)(x-2)=0#

That is #x=7# or #x=2#

#color(white)("XXX")#x-intercepts: #=7# and #2#

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