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How do you find the VERTEX of a parabola #y=x^2+7x+12#?

1 Answer

Sep 8, 2015

Use the method of completing the square to convert to vertex form and get the vertex at #(-7/2, -1/4)#

Explanation:

Vertex form: #y=m(x-a)^2+b# with vertex at #(a,b)#

#y=x^2+7x+12#

#rarr y= x^2+7x+(7/2)^2+12 -(7/2)^2#

#rarr y = (x+7/2)^2 + (48/4 - 49/4)#

#rarr y = (x- (-7/2))^2 + (-1/4)#

#color(white)("XXXXXX")#which is the vertex form with the vertex at #(-7/2,-1/4)#

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