How do you find the vertex of a parabola # y= 1/3[x-1]^2+2 #?

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Answer 1 · 2015-07-18T22:46:37

The vertex is at #color(red)((1,2)#.

#y = -1/3(x-1)^2+2#

The vertex form for the equation of a parabola is

#y = a(x-h)^2 + k#, where (#h, k#) is the vertex of the parabola.

By comparing the two equations, we see that #h = 1# and #k = 2#.

The vertex is at (#1,2#).

graph{-1/3(x-1)^2+2 [-5, 6, -5, 5]}