How do you find the vertex of a parabola #f(x)=x^2+7x+6#?

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How do you find the vertex of a parabola #f(x)=x^2+7x+6#?

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Answer 1 · 2015-07-08T19:34:35

The vertex is located at #(-7/2,-25/4)#

Explanation:

Given #f(x)=x^2+7x+6#

Complete the square
#color(white)("XXXX")##=x^2+7x +(7/2)^2 -(7/2)^2 +6#
Simplify into vertex form
#color(white)("XXXX")##=(x+7/2)^2 -25/4#
or
#color(white)("XXXX")##=(x- (-7/2))^2+(-25/4)#
#color(white)("XXXX")##color(white)("XXXX")#which is the vertex form with vertex at #(-7/2,-25/4)#

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How do you find the vertex of a parabola #f(x)=x^2+7x+6#?

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