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How do you find the slope of the line perpendicular to $y = - 3 x + 9$ $y = -3x + 9$ ?

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Apr 14, 2015

If a line has a slope of $m$ $m$
any perpendicular to it has a slope of $- \frac{1}{m}$ $-1/m$

$y = - 3 x + 9$ $y=-3x+9$
is an equation in the slope y-intercept form where the slope is $- 3$ $-3$

Therefore the slope of any line perpendicular to this line is $\frac{1}{3}$ $1/3$

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