How do you find the second derivative of #y=1/x#?

1 Answer
Jim G.
Jan 25, 2017

#(d^2y)/(dx^2)=2/x^3#

Explanation:

differentiate using the #color(blue)"power rule"#

#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(d/dx(ax^n)=nax^(n-1))color(white)(2/2)|)))#

#y=1/x=x^-1#

#rArrdy/dx=-x^-2#

To obtain the second derivative, differentiate #dy/dx#

#rArr(d^2y)/(dx^2)=2x^-3=2/x^3#

Related questions
See all questions in Chain Rule
Impact of this question
25624 views around the world
You can reuse this answer
Creative Commons License