How do you find the second derivative of #f(x)=ln(7x^2e^x\sin x)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Shwetank Mauria Mar 31, 2018 #(d^2f) /(dx^2)=-2/x^2-csc^2x# Explanation: As #f(x)=ln(7x^2e^xsinx)# i.e. #f(x)=ln7+2lnx+x+lnsinx# Hence #(df)/(dx)=2/x+1+1/sinx*cosx# = #2/x+1+cotx# or #(d^2f) /(dx^2)=-2/x^2-csc^2x# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 2249 views around the world You can reuse this answer Creative Commons License