How do you find the quotient of #(5ab - 10b^2 + 15bc) ÷ 5b#? Algebra Rational Equations and Functions Division of Polynomials 1 Answer Alan P. Oct 28, 2015 It is possible to factor #(5ab-10b^2+15ab)# to determine that #(5ab-10b^2+15bc)div 5b = a-2b+3c# Explanation: #(5ab-10b^2+15bc)div 5b# #color(white)("XXX") =( cancel(5b)(a-2b+3c))/(cancel(5b))# Answer link Related questions What is an example of long division of polynomials? How do you do long division of polynomials with remainders? How do you divide #9x^2-16# by #3x+4#? How do you divide #\frac{x^2+2x-5}{x}#? How do you divide #\frac{x^2+3x+6}{x+1}#? How do you divide #\frac{x^4-2x}{8x+24}#? How do you divide: #(4x^2-10x-24)# divide by (2x+3)? How do you divide: #5a^2+6a-9# into #25a^4#? How do you simplify #(3m^22 + 27 mn - 12)/(3m)#? How do you simplify #(25-a^2) / (a^2 +a -30)#? See all questions in Division of Polynomials Impact of this question 5165 views around the world You can reuse this answer Creative Commons License