How do you find the ordered pairs for y=8x?

1 Answer
EZ as pi
Apr 28, 2018

You can find any number of ordered pairs by choosing an #x#-value and calculating a #y#-value

Explanation:

The equation #y = 8x# means that the value of #y# is #8# times bigger than the value of #x#.

To find ordered pairs (#x,y#), choose several #x# values and then multiply each by #8# to find the corresponding #y# values.

If #x# = 3, then #y=3xx8=24" "# which gives:#" "(3,24)#
If #x# = 5, then #y=5xx8=40" "# which gives:#" "(5,40)#
If #x# = -2 then #y=-2xx8=-16" "# which gives:#" "(-2,16)#
If #x# = 0, then #y=0xx8=0" "# which gives:#" "(0,0)#

etc.

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