How do you find the limit of $sqrt(x^2- 3x)$ as x approaches 3?

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Answer 1 · 2015-04-12T01:28:39

If $f(a)$ exists then the
$lim_(xrarra) f(x) = f(a)$

For $f(x) = sqrt(x^2-3x)$

$f(3) = sqrt(0) = 0$

So
$lim_(xrarr3)sqrt(x^2-3x) = 0$

How do you find the limit of sqrt(x^2- 3x)sqrt(x^2- 3x) as x approaches 3?