How do you find the intervals of increasing and decreasing using the first derivative given y=x+4/x?

1 Answer
Mar 17, 2017

The intervals of increasing are x in ]-oo,-2[uu]2,+oo[
The intervals of decreasing are x in ]-2,0[uu]0,2[

Explanation:

We need

(1/x)'=-1/x^2

The domain of y is D_y=RR-{0}

We calculate the first derivative

y=x+4/x

dy/dx=1-4/x^2

To find the critical points, we calculate the values of x when dy/dx=0

when

1-4/x^2=0

1=4/x^2

x^2=4

Therefore, x=-2 and x=2

We can build the chart

color(white)(aaaa)xcolor(white)(aaaa)-oocolor(white)(aaaa)-2color(white)(aaaaaaaa)0color(white)(aaaaaaa)2color(white)(aaaaa)+oo

color(white)(aaaa)x+2color(white)(aaaaaa)-color(white)(aaaa)+color(white)(aaaa)||color(white)(aaa)+color(white)(aaaa)+

color(white)(aaaa)x-2color(white)(aaaaaa)-color(white)(aaaa)-color(white)(aaaa)||color(white)(aaa)-color(white)(aaaa)+

color(white)(aaaa)dy/dxcolor(white)(aaaaaaaa)+color(white)(aaaa)-color(white)(aaaa)||color(white)(aaa)-color(white)(aaaa)+

color(white)(aaaa)ycolor(white)(aaaaaaaaaa)color(white)(aaaa)color(white)(aaa)||color(white)(aaa)color(white)(aaaa)

The intervals of increasing are x in ]-oo,-2[uu]2,+oo[

The intervals of decreasing are x in ]-2,0[uu]0,2[