How do you find the intercepts for #5y=5x+15#?

1 Answer
Alan P.
Jun 28, 2015

y-intercept #= 3#
x-intercept #=-3#

Explanation:

The y-intercept of an equation is the value of #y# where the equation's line crosses the y-axis; that is it is the value of #y# when #x=0#
Substituting #x=0# in #5y=5x+15# gives
#color(white)("XXXX")##5y = 5(0)+15#
#color(white)("XXXX")##y = 3#

Similarly, the x-intercept of an equation is the value of #x# when #y=0#
Substituting #y=0# in #5y=5x+15# gives
#color(white)("XXXX")##5(0) = 5x+15#
#color(white)("XXXX")##5x = -15#
#color(white)("XXXX")##x=-3#

Related questions
See all questions in Intercepts by Substitution
Impact of this question
1579 views around the world
You can reuse this answer
Creative Commons License