How do you find the integral of #(sec^2 x)(tan^2 x) dx#?

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How do you find the integral of #(sec^2 x)(tan^2 x) dx#?

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Answer 1 · 2018-06-22T14:08:45

#(tan^3x)/3+C#

Explanation:

By making a substitution, #tanx#= #U#, you will get #dU# = #sec^2xdx#. Therefore, #dx#= #(dU)/sec^2x#. Then the integral will become:
#intU^2dU#. Substitute the value of U and obtain the result.

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How do you find the integral of #(sec^2 x)(tan^2 x) dx#?

1 Answer

Explanation:

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