How do you find the integral of (e^(-1/x)) / x^2?

1 Answer
Truong-Son N.
Jun 20, 2015

At first, I was thinking why it was written like this. It makes sense... and this is NOT integration by parts. This can be done by u-substitution.

= int e^"-1/x"/x^2dx = int e^"-1/x"*1/x^2dx

Let:
u = e^"-1/x"
du = e^"-1/x"*1/x^2dx

This is rather interesting; there's no need to use u here. We have the whole thing as du.

=> int du

= u + C

= e^"-1/x" + C

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