How do you find the integral of $6x ln x dx$ ?

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Answer 1 · 2015-07-17T12:56:44

I found: $3x^2[ln(x)-1/2]+c$

I would try By Parts:
$int6xln(x)dx=6x^2/2ln(x)-int6x^cancel(2)/2*1/cancel(x)dx=$
$=3x^2ln(x)-int3xdx=$
$=3x^2ln(x)-3x^2/2+c=$
$=3x^2[ln(x)-1/2]+c$

How do you find the integral of 6x ln x dx 6x ln x dx ?