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How do you find the integral of #6x ln x dx #?

1 Answer

Jul 17, 2015

I found: #3x^2[ln(x)-1/2]+c#

Explanation:

I would try By Parts:
#int6xln(x)dx=6x^2/2ln(x)-int6x^cancel(2)/2*1/cancel(x)dx=#
#=3x^2ln(x)-int3xdx=#
#=3x^2ln(x)-3x^2/2+c=#
#=3x^2[ln(x)-1/2]+c#

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