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How do you find the general solutions for #sqrt(3) - 2Sin(6x) = 0#?

1 Answer

Aug 22, 2015

#x = 10^o +-n*60^ocolor(white)("XXXX")orcolor(white)("XXXX")x=20^o +-n*60^o#
#color(white)("XXXXXXXX")"for "AA n in ZZ#

Explanation:

#sqrt(3)-2sin(6x) = 0#
#rArrcolor(white)("XXXX")sin(6x) = sqrt(3)/2#

#rArr 6x = 60^o +- n*360^ocolor(white)("XXX")orcolor(white)("XXX")6x = 120^o +-n*360#

#rArr x = 10^o +- n*60^o color(white)("XXXX")orcolor(white)("XXX")x=20^o +-n*60^o#

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