# How do you find the general form of the line with slope -2 passing through the point (-4, 6)?

##### 3 Answers

Now put (-4,6) into the equation to find the specific equation

#### Explanation:

#"the equation of a line in "color(blue)"general form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By+C=0)color(white)(2/2)|)))#

#"where A is a positive integer and B, C are integers"#

#"obtain the equation in "color(blue)"slope-intercept form"#

#•color(white)(x)y=mx+b#

#"where m is the slope and b the y-intercept"#

#"here "m=-2#

#y=-2x+blarrcolor(blue)"is the partial equation"#

#"to find b substitute "(-4,6)" into the partial equation"#

#6=8+brArrb=6-8=-2#

#y=-2x-2larrcolor(red)"in slope-intercept form"#

#"subtract "2x-2" from both sides"#

#2x+y+2=0larrcolor(red)"in standard form"#

#### Explanation:

Slope is always -2 which means it is a straight line where

i.e. **decreases** by 2 for every 1 that

The general form will therefore be:

**y=-2x +c** (where

To find

(when

The point (-4, 6) tells us that when

**c=-2**

so the equation for the line is **y=-2x-2**

check this by putting x=-4 into the equation and seeing if y = 6:

y = -2(-4) - 2 = 8 - 2 = 6 (looks correct)