How do you find the fourth term of ((2x-z)^2 )^6?

1 Answer
Alan P.
May 27, 2015

((2x-z)^2)^6 = (2x-z)^12

The fourth term of this expansion is
color(red)(12C4) * (2x)^4 * (-z)^(12-4)

= (12!)/((4!)(8!)) * 16x^4 * z^8

= (495) *16x^4z^8

=7920x^4z^8

color(red)("Note")
I'm not certain of the current notation standard for this expression: "12 Choose 4" and have used the form I learned more than 50 years ago.

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