How do you find the excluded value and simplify $\frac{3 x^{2} - 5 x - 28}{x^{2} + 3 x - 28}$ $(3x^2-5x-28)/(x^2+3x-28)$ ?

Question

How do you find the excluded value and simplify $\frac{3 x^{2} - 5 x - 28}{x^{2} + 3 x - 28}$ $(3x^2-5x-28)/(x^2+3x-28)$ ?

2 Answers

Impact of this question

2019 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-11-07T15:16:50

$\frac{3 x + 7}{x + 7}$ $(3x+7)/(x+7)$

Explanation:

$\frac{3 x^{2} - 5 x - 28}{x^{2} + 3 x - 28}$ $(3x^2-5x-28)/(x^2+3x-28)$

= $\frac{3 x^{2} - 12 x + 7 x - 28}{x^{2} + 7 x - 4 x - 28}$ $(3x^2-12x+7x-28)/(x^2+7x-4x-28)$

= $\frac{3 x \cdot (x - 4) + 7 \cdot (x - 4)}{x \cdot (x + 7) - 4 \cdot (x + 7)}$ $[3x*(x-4)+7*(x-4)]/[x*(x+7)-4*(x+7)]$

= $\frac{(3 x + 7) (x - 4)}{(x - 4) (x + 7)}$ $[(3x+7)(x-4)]/[(x-4)(x+7)]$

= $\frac{3 x + 7}{x + 7}$ $(3x+7)/(x+7)$

Answer 2 · 2017-11-07T15:19:02

$= \frac{3 x + 7}{x + 7} = 1 + \frac{2 x}{x + 7}$ $=(3x+7)/(x+7) = 1 + (2x)/(x+7)$

Explanation:

$N r = 3 x^{2} - 5 x - 28 = 3 x^{2} - 12 x + 7 x - 28$ $Nr = 3x^2-5x-28= 3x^2-12x+7x-28$
$= 3 x (x - 4) + 7 (x - 4) = (x - 4) (3 x + 7)$ $=3x(x-4)+7(x-4) = (x-4)(3x+7)$

$D r = x^{2} + 3 x - 28 = x^{2} + 7 x - 4 x - 28$ $Dr = x^2+3x-28=x^2+7x-4x-28$
$= x (x + 7) - 4 (x + 7) = (x - 4) (x + 7)$ $=x(x+7)-4(x+7)=(x-4)(x+7)$

$Nr/Dr = (cancel(x-4)(x+7)) /(cancel(x-4)(4x+7)$

$=(3x+7)/(x+7) = 1 + (2x)/(x+7)$

Science

Math

Humanities

... and beyond

How do you find the excluded value and simplify $\frac{3 x^{2} - 5 x - 28}{x^{2} + 3 x - 28}$ $(3x^2-5x-28)/(x^2+3x-28)$ ?

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you find the excluded value and simplify (3x^2-5x-28)/(x^2+3x-28)3x2−5x−28x2+3x−28 (3x^2-5x-28)/(x^2+3x-28)?

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question

How do you find the excluded value and simplify $\frac{3 x^{2} - 5 x - 28}{x^{2} + 3 x - 28}$ $(3x^2-5x-28)/(x^2+3x-28)$ ?