How do you find the equation, x-intercept, and the y-intercept for the line with an x-intercept of 2, and y-intercept of -3?

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Answer 1 · 2018-03-09T14:42:58

Equation of the line is #color(green)(2y = 3x - 6#

The x-intercept is where a line crosses the x-axis. ie y = 0.

The y-intercept is where the line crosses the y-axis. ie x = 0.

Given : x-intercept = 2 or the point is #(x_1 = 2, y_1 = 0)#

y-intercept = -3 or the point is #(x_2 = 0, y_2 = -3)#

Knowing two points on the line, equation can be formed using

#(y - y_1) / (y_2 - y_1) = (x - x_1) / (x_2 - x_1)#

#(y - 0) / (-3 - 0) = (x - 2) / (0 -2)#

#y / -3 = (x - 2) / -2#

Equation of the line is #color(green)(2y = 3x - 6#

Answer 2 · 2018-03-09T14:53:47

#3x-2y=6#

Equation of a line whose #x# intercept is #a# and #y#-intercept is #b# is

#x/a+y/b=1#

Hence equation of a line whose #x# intercept is #2# and #y#-intercept is #-3# is

#x/2+y/(-3)=1#

or #3x-2y=6#