# How do you find the domain of f(x)=Ln(3x+2)?

Nov 18, 2016

The argument of the $\ln$ function must be $> 0$

#### Explanation:

$\to 3 x + 2 > 0$ subtract $2$:
$\to 3 x > - 2$ divide by $3$:
$\to x > - \frac{2}{3}$
On the other side, there is no maximun for $x$, so:
$- \frac{2}{3} < x < + \infty$ or $\left(- \frac{2}{3} , + \infty\right)$

graph{ln(3x+2) [-5.37, 19.94, -6.49, 6.17]}