How do you find the domain and range of $y = -tan(x - pi/2)$ ?

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Answer 1 · 2017-07-23T11:44:28

Domain : ${ x| x != pi + pi*n , n = ... -1,0,1.. }$ in radians.
Range: All reals

The domain is the values that x can take in the function. The

tangent functions have vertical asymptotes (at the end of every

period) and x has no values at these points, but does exist

everywhere else. So domain is as

$x-pi/2 != pi/2 or x != pi/2 +pi/2 or x != pi$ and their multiples.

Domain : ${ x| x != pi + pi*n , n = ... -1,0,1.. }$ in radians.

Range : Tangent functions have no maximums or minimums, so the

range for a tangent function is all reals. [Ans]

How do you find the domain and range of y = -tan(x - pi/2)y = -tan(x - pi/2)?