How do you find the derivatives of #y=lnabs(3x+4)#?

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How do you find the derivatives of #y=lnabs(3x+4)#?

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Answer 1 · 2018-07-31T13:43:40

#3/(3x+4)#

Explanation:

#d/dx[ln(abs(3x+4))]#
=#1/abs(3x+4)*d/dx[abs(3x+4)]#
=#[(3x+4)/abs(3x+4)*d/dx[3x+4]]/abs(3x+4)#
=#[3*d/dx[x]+d/dx[4]]/(3x+4)#
=#[3*1+0}/(3x+4)#
=#3/(3x+4)#

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How do you find the derivatives of #y=lnabs(3x+4)#?

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