How do you find the derivative using the power chain rule of #y=(cos(x^4)+x^3))^8#? Calculus Basic Differentiation Rules Chain Rule 1 Answer bp Aug 10, 2015 #8(cos x^4 +x^3)^7 *(3x^2 -4x^3 sin x^4)# Explanation: #dy/dx = 8 (cos x^4 +x^3)^7 d/dx (cos x^4 +x^3)# = #8(cos x^4 +x^3)^7 * (d/dx cosx^4 +d/dx x^3)# =#8(cos x^4 +x^3)^7 *(-sin x^4 4x^3 +3x^2)# =#8(cos x^4 +x^3)^7 (3x^2 -4x^3 sin x^4)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1748 views around the world You can reuse this answer Creative Commons License