How do you find the derivative of #y=tan^2(3x)#?

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Answer 1 · 2014-09-08T17:37:26

By using the Chain Rule twice,

#y'=6tan(3x)sec^2(3x)#

Let us look at some details.
By Chain Rule,

#y'=2tan(3x)cdot(tan(3x))'#

by another application of Chain Rule to #(tan(3x))'#,

#=2tan(3x)cdot sec^2(3x)cdot3#

by cleaning up a bit,

#=6tan(3x)sec^2(3x)#