# How do you find the derivative of y = sqrt(2x - x^2)?

$y = {\left(2 x - {x}^{2}\right)}^{\frac{1}{2}}$
$y ' = \frac{1}{2} {\left(2 x - {x}^{2}\right)}^{\frac{1}{2} - 1} \cdot \left(2 - 2 x\right) =$
$= \frac{1 - x}{\sqrt{2 x - {x}^{2}}}$