How do you find the derivative of #y=lnx^3#?

1 Answer
Jan 23, 2017

I got #y'=3/x#

Explanation:

We can use one of the properties of logs that allow us to write it as:
#y=3ln(x)#
We can then derive as usual:
#y'=3*1/x#

We can also use the Chain Rule deriving the log first as it is and multiply by the derivative of the argument:
#y'=1/x^3*3x^2=# simplify:
#=3/x#
...again