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How do you find the derivative of #y=ln(x+3)ln(x-1)#?

1 Answer

Jan 13, 2017

#d/(dx)(ln(x+3)ln(x+1)) = ln(x+1)/(x+3)+ln(x+3)/(x+1)#

Explanation:

We can use the product rule:

#d/(dx)( f(x)*g(x)) = f'(x) g(x) +f(x) g'(x)#

So:

#d/(dx)(ln(x+3)ln(x+1)) = ln(x+1)/(x+3)+ln(x+3)/(x+1)#

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